How To Calculating the quantity of materials for the 100 sq.ft of tile flooring.
How To Calculating the quantity of materials for the 100 sq.ft of tile flooring.
How To Calculating the quantity of materials for the 100 sq.ft of tile flooring.
Let us fix the tile of ( 2′ × 2′ ) size in the room of area ten ft. × ten ft.
Let us use cement mortar of 1:4 ratio having 40-mm. thickness to the fix these tiles.
Calculation.
1 – The number of the tiles required
= room area ÷ tile area
= [( 10ft × 10 ft )÷ ( two ft × 2 ft )]
= [100 sqft ÷ Four sqft ]
= 25-nos.
The wet volume of the cement mortar
= room area × mortar thickness
= 100 sq. ft. × (Forty × 0.00328084) ft
( One-mm = 0.00328084 ft. )
= 100 sqft × 0.13123 ft
= 13.123 cu-ft
Dry volume of the cement mortar
= 1.33 × wet mortar volume
= [ 1.33 × 13.123 cu-ft ]
= 17.453 cu-ft
= 0.4942-cum
( One – cu ft = 0.0283168 cum )
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2 – The volume of the cement required
= dry volume of the floor mortar × ( ratio of cement ÷ total ratio )
= [17.453 cu ft × ( One ÷ ( One + 4 ))]
= [ 17.453 × 0.2 ]
= 3.4906 – cu-ft
= 0.09884-cum
( One – cu-ft = 0.0283168 cum. )
As u know that the density of cement = 1440kg/cum.
So, the total qty of cement required in kgs.
= [ 0.09884 cum × 1440 kg/cum ]
= 142.3296 kg
1 bag of the cement weighs 50-kg
The number of the cement bags required
= [ 142.329 ÷ 50 ]
= 2.84-bags.
3 – The volume of the sand required
= dry volume of the floor mortar × ( ratio of sand ÷ total ratio )
= [17.453 cu ft.× ( Fore ÷ (1+4 ))]
= [17.453 cu ft.× 0.8]
= 13.9624 cu-ft.
= 0.3953 cum
or
Volume of the sand
= volume of cement × Fore
= [ 0.09884 cum.× fore ]
= 0.3953-cum.
or
Volume of the sand
= total dry volume- the volume of the cement
= [ 0.49421 cum – 0.09884 cum ]
= 0.3953 cum
Density of the dry sand = 1602 kg/cum.
Weight of the sand required
= [ 0.3953 cum × 1602 kg/cum ]
= 633.387 kg
Thank U For Read This Article.
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